2/5x^2+2x=1/5

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Solution for 2/5x^2+2x=1/5 equation: 


x in (-oo:+oo)

(2/5)*x^2+2*x = 1/5 // - 1/5

(2/5)*x^2+2*x-(1/5) = 0

(2/5)*x^2+2*x-1/5 = 0

2/5*x^2+2*x-1/5 = 0

DELTA = 2^2-(-1/5*2/5*4)

DELTA = 108/25

DELTA > 0

x = ((108/25)^(1/2)-2)/(2/5*2) or x = (-(108/25)^(1/2)-2)/(2/5*2)

x = 5/4*((108/25)^(1/2)-2) or x = -5/4*((108/25)^(1/2)+2)

x in { -5/4*((108/25)^(1/2)+2), 5/4*((108/25)^(1/2)-2) }

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